CBSE BOARD X, asked by mohdsahban683, 7 months ago

100 kj of energy followed in one minute and 40 second in an electric device of resistance 40 ohm calculate the potential difference at the end of the device.

Answers

Answered by jeys295

7

Answer:

V=IR

V=100×40

V=4000

is the answer

Answered by 10216pranith

0

Answer:

v = 400 confirm

Explanation:

mark this it's the correct answer.

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