Question

100 mL of O2 is collected over water at 23°C and 800 torr. Compute the standard volume
of the dry oxygen. Vapour pressure of water at 23°C is 21.1 torr. (1 torr = 1 mm Hg)​

Answer 1

Answer:

Let the volume of

be x mL <br> Volume of

<br> Volume of

<br> (a).

<br> (b).

<br> Volume of

absorbed by

<br>

<br> Volume of gaseous reactant

volume of gaseous production

constraction <br>

<br>

<br>

<br>

<br>

<br>

<br> Volume of

<br> Volume of

<br> Volume of

Answer 2

Answer:

Correct option is

B

V=94.54mL

V1=100mL

V2=?P1=779mm

P2=760mm

T1=23∘C=23+273             

T2=293K

                   =296K

T1P1V1=T2P2V2

V2=P2T1P1V1T2=760×296779×100×273=94.54mL