100 points question
7.5 ml of a gaseous hydrocarbon was exploded with 36 ml of oxygen. The volume of gases on cooling was found to be 28.5 ml, 15 ml of which was absorbed by KOH and the rest was absorbed in a solution of alkaline pyrogallol. If all volumes are measured under the same conditions, deduce the formula of the hydrocarbon.
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Heya....✋
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Heya User,
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Solution:
15 ml is CO2
=> [ 15/7.5 = 2 atoms of C per molecule ]
13.5 ml is O2
So, 22.5 ml of O2 was used
=> [ 7.5 ml goes into water, so 7.5 ml of H2 ]
Hence, the gas is Ethyne is “C2H2”.
{ Sorry, but I am not sure about my given answer }
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Thank You....!!!
Here's your answer
______________________
Solution:
15 ml is CO2
=> [ 15/7.5 = 2 atoms of C per molecule ]
13.5 ml is O2
So, 22.5 ml of O2 was used
=> [ 7.5 ml goes into water, so 7.5 ml of H2 ]
Hence, the gas is Ethyne is “C2H2”.
{ Sorry, but I am not sure about my given answer }
______________________
Thank You....!!!
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