find the zeroes of the polynomial x*square+1/6x-2 and verify the relation between the coefficients and the zeroes of the polynomial
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x^2 + 1/6x - 12
6x^2 + x - 2
6x^2 + [ 9 - 8 ] -1 2
6x^2 + 9x - 8x - 12
3x [ 2x + 3] - 4 [ x + 3]
(3x - 4) ( 2x + 3)
3x - 4 2x + 3
x = 4/3 x = -3/2
sum of zeroes = -b/a
= -1 / 6
products of zeros = c/a
= -12/6 = 2
hope this helps ☺☺
6x^2 + x - 2
6x^2 + [ 9 - 8 ] -1 2
6x^2 + 9x - 8x - 12
3x [ 2x + 3] - 4 [ x + 3]
(3x - 4) ( 2x + 3)
3x - 4 2x + 3
x = 4/3 x = -3/2
sum of zeroes = -b/a
= -1 / 6
products of zeros = c/a
= -12/6 = 2
hope this helps ☺☺
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