100ml of 0.1m NaCl and 100ml of 0.2m NaOH are mixed. What is the change of PH of NaCl solution
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Explanation:
ANSWER
NaOH+CH
3
COOH⟶CH
3
COONa+H
2
O
10 m mol 20 m mol
0 10 m mol 10 m mol
Now it is a buffer
pH=pk
a
+log[
acid
salt
]
pH=4.74+log1=4.74
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