106,159,265,Find the HCF of the given number by prime factorisation and continued division method.
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Answered by
53
Prime factorisation method :
106 = 2 × 53
159 = 3 × 53
265 = 5 × 53
Therefore ,
HCF ( 106 , 159 , 265 ) = 53
I hope this helps you.
: )
106 = 2 × 53
159 = 3 × 53
265 = 5 × 53
Therefore ,
HCF ( 106 , 159 , 265 ) = 53
I hope this helps you.
: )
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Answered by
30
By Prime factorisation method:
The prime factors of 106 = 2 x 53
The prime factors of 159 = 3 x 53
The prime factors of 265 = 5 x 53
The common factors is 53.
Therefore the HCF is 53.
By Division method:
106)159(1
- 106
-------------
53)106(2 Therefore HCF od 106 and 159 is 53.
106
-----------------------
x
53)265(5
265
--------------- Therefore, the HCF of 53 and 265 is 53.
x
Thus HCF is 53.
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