Question

106,159,265,Find the HCF of the given number by prime factorisation and continued division method.

Answer 1

Prime factorisation method :

106 = 2 × 53

159 = 3 × 53

265 = 5 × 53

Therefore ,

HCF ( 106 , 159 , 265 ) = 53

I hope this helps you.

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Answer 2

By Prime factorisation method:

The prime factors of 106 = 2 x 53

The prime factors of 159 = 3 x 53

The prime factors of 265 = 5 x 53

The common factors is 53.

Therefore the HCF is 53.

By Division method:

106)159(1

- 106

-------------

53)106(2 Therefore HCF od 106 and 159 is 53.

106

-----------------------

x

53)265(5

265

--------------- Therefore, the HCF of 53 and 265 is 53.

x

Thus HCF is 53.