English, asked by Anonymous, 2 months ago

108a²-3(b-c)²

Factorise it!​

Answers

Answered by rajenderduhoon
2

Explanation:

3(36^2-(b-c)^2

(6a)^2-(b-c)^2

*(6a+b-)

hope its useful

Answered by Anonymous
10

108a² - 3(b-c)²

3[36a² - (b-c)²]

3[(6a)² - (b-c)²]

3[{6a + (b-c)} {6a - (b-c)}]

3[{6a + b - c} {6a - b + c}]

3{6a + b - c}{6a - b + c}

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