10g of hydrogen and 64g
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Answer:2H
10 g of hydrogen (molar mass 2 g/mol) =
2 g/mol
10 g
= 5 mol
64 of oxygen (molar mass 32 g/mol) =
32 g/mol
64 g
= 2 mol
As per the balanced chemical equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water.
2 moles of oxygen will react with 2×2=4 moles of hydrogen to form 4 moles of water.
Here, oxygen is the limiting reagent and hydrogen is the excess reagent.
Hence, option B is correct
Explanation: its the wrong subject but....okay.
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