Question

10g of ice at -10°C is added to 10 g of water at 85°C. What is the final temperature and amount of ice left in the system

Answer 1

Answer:

80.476

Explanation:

Let the final temperature acquired be t° C

Heat gained by the ice=mass of ice*specific heat capacity of ice*change in temperature

Heat gained=0.01 kg*2.108*(t -(-10°))

=0.02108*(t+10°)

Heat lost by water=mass of water*specific heat capacity of water*change in temperature

Heat lost=0.01 kg*4.187*(85-t°)

=0.04187*(85°-t°)

By principal of calorimetry,

Heat lost=Heat gained

0.04187*(85°-t°)=0.02108*(t°+10°)

(85°-t°)=0.05(t°+10°)

85°-t°=0.05t°+0.5

85-0.5=0.05t+t

84.5=1.05t

t=84.5/1.05

t=80.476.