10th maths Triangles
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so what are you asking for complete your question
silverparrot7:
find length of each side
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Answer:
In ΔABC:AB=4
BC=12
AC=20
In ΔDEF:DF=40
EF=24
ED=8
Step-by-step explanation:
As given, ΔABC is similar to ΔDEF.
So, (x-1)/8=(2x+2)/(2x+9)=4x/8x
⇒(x-1)/8=4x/8x
⇒(x-1)8=1/2
⇒2(x-1)=8
⇒2x-2=8
⇒2x=10
⇒x=10/2=5
Now put the vale of x in sides of ΔABC:
AB=x-1=5-1=4
BC=2x+2=2×5+2=12
AC=4x=4×5=20
Again, put x=5 in sides of ΔDEF:
DF=8x=8×5=40
EF=3x+9=3×5+9=15+9=24
I hope it helps u...
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