Question

10V battery is connected in a electric circuit. Between A and B points 20 ohms and 30 ohms
resisters connected to get least resistance in the circuit. Find the resultant resistance
between A and B and find current in the circuit​

Answer 1

Answer:

Least resistance in circuit can be obtained by parallel combination.

Answer 2

Answer:

The resistance between A and B is 12Ω and the current in the circuit​ is 0.83A.

Explanation:

Given a battery of potential, $V=10V$

          resistors of resistances, $R_{1}= 20 \Omega\ \&\ R_{2}=30 \Omega$

To get the least resultant resistance, the resistors must be connected in parallel.

Then the resultant resistance is

                               $\frac{1}{R} =\frac{1}{R_{1} }+\frac{1}{R_{2} }=\frac{1}{20 }+\frac{1}{30 }$

                                                     $=\frac{30+20}{20\times 30 }=\frac{50}{600 }$

                                                     $=\frac{1}{12 }$

Therefore, the resultant resistance between A and B is 12Ω.

From Ohm's law,

                               $V=IR\implies I=\frac{V}{R}$

                                                        $=\frac{10}{12} =0.83A$

The current in the circuit​ is 0.83A.