Math, asked by jyotisonijyoti48, 9 months ago

11.
Age of Rohit is 5 more than twice of Pradeep's age. 6 year ago, age of Pradeep
1
was
of Rohit's age. Find their ages.

Answers

Answered by TheSentinel
27

Corrected Question:

Age of rohit is 5 more than twice the age of pradeep .6 year ago age of pradeep was 1/3 of rohits age. Find their age .

Answer:

The ages of Rohit and Pradeep are : 39 years and 17 years respectively.

Given:

➛Age of rohit is 5 more than twice the age

of pradeep.

➛6 year ago age of pradeep was 1/3 of

rohits age.

To Find:

The ages of Rohit and Pradeep.

Solution:

We are given,

➛Age of rohit is 5 more than twice the age

of pradeep.

➛6 year ago age of pradeep was 1/3 of

rohits age.

Let the age of Rohit is 'm' and age of Pradeep is 'n'.

according to the conditions in the question,

➞m = 2n + 5

⛬ m - 2n = 5............ (1)

Now, According to second condition,

n - 6 =  \large \rm \dfrac{1}{3} ( m - 6 )

⛬ 3n - 12= m .......... (2)

by substituting m = 3n -12 in the first equation we get,

➪( 3n - 12 ) -2n = 5

⛬ 3n - 12- 2n = 5

➪n - 12 = 5

➪n = 12 + 5

n = 17

Now, substitute n = 17 in the first equation,

➪m - 2(17) = 5

⛬ m - 34 =5

➪m = 34 + 5

m = 39

therefore age of Rohit is 39 and the age of Pradeep is 17.

Answered by ruchiverma19032007
3

Answer:

39 and 17 age

this is a answers

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