Chemistry, asked by shashank2049, 8 months ago

11. Calculate the ionic strength (M) of 50 ml of 0.75 % (w/v) NaCl solution?
a. 0.128
b. 0.256
c. 7.8
d. 0.064​

Answers

Answered by udishvijay42
0

Answer:

So basically we have to find what is the ionic strength of 0.75g/100ml of Nacl solution

We know that 1M=58.44g/1L

or 58.44g/1L=1M

0.75g/100ml=1M*0.75g*1000ml/(58.5g*100ml)

                    =0.128 M

option (b) (0.128)

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