Math, asked by mohitsingh4032, 3 months ago

11. Divide 243 into three parts such that half of the first part, one-third of the
second part and one-fourth of the third part are all equal.

Answers

Answered by Khanayaan
4

Answer:

Step-by-step explanation:

Number = 243

Let the number be divided into three parts a,b&c

a+b+c = 243

Now, according to the question ;

(1/2)a = (1/3)b = (1/4)c

(multiply each by LCM of 2,3,4 = 12)

(12/2)a = (12/3)b = (12/4)c

6a = 4b = 3c

a:b = 4/6 = 2:3

b:c = 3:4

a:b:c = 2:3:4

Let the common ratio be x, then

2x + 3x + 4x = 243

9x = 243

x = 27  

Hence the three parts are ;

a = 2x = 2×27 = 54

b = 3x = 3×27 = 81

c = 4x = 4×27 = 108

Answered by srivastavajiya3
0

Answer:

now your points is 40 ok frnd.

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