Question

11.multiply the sum of-3/11 and 5/22 by the product of 4/7 and -14/9​

Answer 1

Answer:

Solution :-

Sum of :-

$\frac{ - 3}{11} + \frac{5}{22}$

L.C.M of 11 , 22 is 22.

$( \frac{ - 3}{11} \times \frac{2}{2} ) + ( \frac{5}{22} )$

$\frac{ - 6}{22} + \frac{5}{22}$

$= \frac{ - 6 + 5}{22}$

$= \frac{ - 1}{22}$

$\sf\therefore Sum\: of \dfrac{-3}{11} , \dfrac{5}{22} = \dfrac{-1}{22}$

Product of :-

$\frac{4}{7} \times \frac{ - 14}{9}$

$= \frac{4 \times - 14}{7 \times 9}$

$= \frac{ - 56}{63} = \frac{-8}{9}$

$\sf\therefore Product\: of \dfrac{4}{7},\dfrac{-14}{9} = \dfrac{-8}{9}$

Product of :-

$\frac{ - 1}{22} \times \frac{ - 8}{9}$

$= \frac{ - 1 \times - 8}{22 \times 9}$

$= \frac{8}{198}$

= $\sf\frac{4}{99}$

Since ,

$multiply \: the \: sum \: of \: \frac{ - 3}{11}and \frac{5}{22}by \: product \: of \: \frac{4}{7} and \frac{ - 14}{9}$

= $\sf\frac{4}{99}$

Answer 2

Answer:

4/99

Step-by-step explanation:

$\frac{ - 3}{11} + \frac{5}{22} \times ( \frac{4}{7} \times \frac{ - 14}{9} ) \\ \frac{ - 6}{22} + \frac{5}{22} \times ( \frac{4}{1} \times \frac{ - 2}{9} ) \\ \frac{ - 6 + 5}{22} \times ( \frac{4 \times - 2}{9} ) \\ \frac{ - 1}{22} \times \frac{ - 8}{9} \\ \frac{1}{11} \times \frac{4}{9} \\ \frac{4}{99}$