Question

11. When a force acts on a body of mass 10 g initially at rest, it acquires a velocity of 15 ms- in 5s. Find the acceleration and final momentum of the body and the magnitude of the force.​

Answer 1

Question

When a force acts on a body of mass 10 g initially at rest, it acquires a velocity of 15 ms- in 5s. Find the acceleration and final momentum of the body and the magnitude of the force.

Solution

Given

• Initial Velocity (u) = 0 m/s
• Final Velocity (v) = 15 m/s
• Time taken (t) = 5s
• Mass of the body (M) = 10g = 10^-2 Kg

To finD

• Acceleration Of The Body
• Magnitude Of Applied Force
• Final Momenta

Acceleration

The rate of change of velocity with respect to time

$\implies \: \sf \: a = \dfrac{v - u}{t} \\ \\ \implies \: \sf \: a = \dfrac{15 - 0}{5} \\ \\ \huge{ \implies \: \boxed{ \boxed{ \sf \: a = 3 \: {ms}^{ - 2} }}}$

Force

An interaction with compels a body of mass M to change its velocity

$\implies \sf \: \: F = Ma \\ \\ \huge{ \implies \ \boxed{ \boxed{ \sf{F = 3 \times {10}^{ - 2} \: N }}}}$

Final Momenta

Momentum is the product of mass and velocity

$\implies \: \sf \: P = Mv \\ \\ \huge{ \implies \: \boxed{ \boxed{ \sf \: P = 15 \times {10}^{ - 2} \: \: Kg. {ms}^{ - 1} }}}$

Answer 2

Answer:

Explanation:

Given :-

Initial Velocity of the body  = 0 m/s

Final Velocity of the body = 15 m/s

Time taken of the body = 5 seconds

Mass of the body = 10 g = 10⁻² Kg

To Find :-

Acceleration of the body.

Magnitude of applied force.

Final momentum.

Solution :-

At First, we will find Acceleration of the body

⇒ a = (v - u)/t

⇒ a = (15 - 0)/5

⇒ a = 3 m/s⁻²

Then, Magnitude of applied force

⇒ F = ma

⇒ F = 3 × 10⁻² N

Now, Final Momentum

⇒ P = mv

⇒ P = 15 × 10⁻² Kg/ms