Question

(111)
sin A - 2 sin^3A/2cos^3A - cosA= tan A​

Answer 1

sinA-2sin³A/2cos³A-cosA

=sinA(1-2sin²A)/cosA(2cos²A-1)

=sinA(cos2A)/cosA(cos2A)

=sinA/cosA

=tanA

Answer 2

Answer:

sinA-2sin³A/2cos³A-cosA

=sinA(1-2sin²A)/cosA(2cos²A-1)

=sinAcos2A/cosAcos2A

=sinA/cosA.

=tanA(R:H:S)

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