Question

112.0 mL of NO2 at STP was liquefied, the density

of the liquid being 1.15 g mL-1

. Calculate the

volume and the number of molecules in the liquid

NO2.

(1) 0.10 mL and 3.01



1022



(2) 0.20 mL and 3.01



1021

(3) 0.20 mL and 6.02



1023

(4) 0.10 mL and 6.02



1021​

Answer 1

Answer:

2

Explanation:

moles of NO2 =112/22400=5×10^-3mol

mass of no2=5×10^-3×46g=0.23g

volume of no2=mass /density =0.23/1.15=0.2ml

number of molecules =5×10^-3×6.023×10^23=3.1×10^-21