11221
Property 6. Ifz, and 2, are two complex numbers, then 2, 2, 512,1-12
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0
Answer:
Answer
Correct option is
C
−i
∣zw∣=1&argz−argw=
2
π
Let ∣z∣=r⇒∣w∣=
r
1
let z=∣z∣(cosA+isinA)=rcisA
&w=∣w∣(cosB+isinB)=
r
1
cisB
∵argz−argw=
2
π
⇒A−B=
2
π
...(1)
z
ˉ
w=(rcis(−A))(
r
1
cisB)=cis(−(A−B))
⇒
z
ˉ
w=cis(−
2
π
)=−i ...{ From 1 }
Hence, option 'C' is correct.
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