11th no. Question...........
Answers
Step-by-step explanation:
Electric Field Intensity is zero in a particular region wrt to a source.
To find:
Relationship between Electric Potential V and distance r
Concept:
Electric Field intensity is a vector index representing the strength of the field produced by the source.
Whereas Electric Potential is a scalar index also representing the strength.
Calculation:
\displaystyle{ \int \: dV = \int \: E \: dr}∫dV=∫Edr
Putting the limits :
\displaystyle{ \int_{V1}^{V2} dV = \int_{r1}^{r2} \: E \: dr}∫
V1
V2
dV=∫
r1
r2
Edr
\implies\displaystyle{ \int_{V1}^{V2} dV = \int_{r1}^{r2} \: 0 \times \: dr}⟹∫
V1
V2
dV=∫
r1
r2
0×dr
\implies V2 - V1 = 0⟹V2−V1=0
\implies V2 = V1⟹V2=V1
\implies V = constant⟹V=constant
So Electric Potential becomes constant .
It becomes independent of