Question

12.04 × 1022 molecules of urea are present in 500 mL of its solution. The molarity of the solution is

Answer 1

Answer:

0.4 is correct answer

Explanation:

Hope the answer

Answer 2

0.4 M is the molarity of the solution having 12.04 × 1022 molecules of urea in 500 ml of its solution.

Explanation:

Data given:

12.04 × 1022 molecules of urea

volume = 500 ml

formula for molarity

molarity (M) = $\frac{number of moles}{volume in litres}$    equation 1

Formula to calculate number of moles from number of molecules given

number of moles = $\frac{number of molecules}{Avogadro number}$    equation 2

I mole of a substance has 6x10^23 molecules of it.

number of moles =  $\frac{12.04 × 1022}{6.02x10^23}$   ( Avogadro number is 6.02 x10^23 atoms)

  number of moles of urea =  0.2

For molarity putting the value in equation 1

Volume is converted into litres as $\frac{500}{1000}$ = 0.5 litre

M = $\frac{0.2}{0.5}$

    = 0.4 M

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