12-1. A car starts from rest and with constant acceleration achieves a velocity of 15 m/s when it travels a distance of 200 m. Determine the acceleration of the car and the time required
Answers
Answered by
8
So we have u= 0m/s, v=15m/s, s= 200m
So,
2as= v^2-u^2
A= V^2 - U^2/2s
= 225/400
=0.5625 m/s^2
V=u+a*(t^2)
15=0+0.5625(t^2)
15-0.5625= t^2
=14.4375=t^2
root14.4375= root(t)
Time= 3.7996710383926659079171860515099 seconds
So I hope you understand it and if there is any mistake please correct it.
Answered by
5
Answer:
a = 0.5625 m/s^2
t = 26.67 s
Explanation:
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