Question

12. 10 yrs ago, a father was 4 times as old as his son, after 20 yrs, he will be twice as old as his son. Find the sons age

Answer 1

let the age of the man at present be X yrs

10yrs ago age of man=(X-10)

10 yrs ago age of son=(X-10)/4

present age of son=((X-10)/4)+10

required equation will be(((X-10)/4)+10+20)×2=(X+20)

implies X=70 yrs

hence present age of son=((70-10)/4)+10=(15+10)=25yrs