Question

12.5 g of H2SO4 dissolve in 90 g of water calculate solute and solution

Answer 1

if you are asking for the ratio I will give the answer
amount of sulphuric acid (H2SO4)=12.5g
amount of water=90g
ratio between them
=12.5/90
=125/900
=25/180
=5/36
and if you are asking for the percentage
then multiply the ratio by 100
=(5/36)×100
=(5/9)×25
=125/9
={13+(8/9)}%
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