Question

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12. a. Ifx: y = 4:7, find 2x + 5y: 3x + 4y.​

Answer 1

this solution wi

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Answer 2

Ans ::3x+4y:8x+5y=29:49

Step-by-step explanation:

Given, xy=35

Let,

3x+4y8x+5y=z

We have to find the value of ‘z’ here..

3x+4y=(8x+5y)z

3x+4y=8xz+5yz

8xz−3x+5yz−4y=0

x(8z−3)+y(5z−4)=0

Dividing by y,

xy(8z−3)+(5z−4)=0

35(8z−3)+(5z−4)=0

Taking 5 as LCM, and taking it to RHS,

3(8z−3)+5(5z−4)=0

24z−9+25z−20=0

49z−29=0

z=2949

z=29:49

Therefore,

3x + 4y : 8x + 5y = 29 : 49

Alternately,

Let,

3x+4y8x+5y=3x+4y8x+5y

Take y common from numerator and denominator and cancel it out,

3x+4y8x+5y=3xy+48xy+5

Put value of xy ,

3x+4y8x+5y=3∗35+48∗35+5

3x+4y8x+5y= 295495

3x+4y8x+5y=2949

3x+4y:8x+5y=29:49