Question

12. Calculate the length of a second's pendulum at place where
acceleration due to gravity is 9.8 m/s.​

Answer 1

Answer:

On earth, the seconds pendulum has a constant length of approximately 1m.  A seconds pendulum is a pendulum whose period is precisely twoseconds; one second for a swing in one direction and one second for the return swing, a frequency of 1/2 Hz.

Since the pendulum reaches its extreme position twice in one oscillation, the time period of a seconds pendulum is 2 seconds.

The time period of a simple pendulum of length L is

=2‾‾√

Put T=2 seconds

g = 9.8m/s/s

= 2  = 0.994

On earth, the seconds pendulum has a constant length of approximately 1m

Explanation: