12. Find three numbers in AP so that their sum is 21 and the product of the last two is 84.
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Answered by
3
Answer:
let the terms be a-d,a , a+d
(a-d)+a+(a+d)=21
3a=21
a=7
a(a+d)=84
7(7+d)=84
7+d=12
d=5
a-d=2
a=7
a+d=12
they are 2,7,12
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Answered by
2
let the terms be a-d,a , a+d
(a-d)+a+(a+a)=21
3a=21
a=7
a(a+d)=84
7(7+d)=84
7+d=12
d=5
a-d=2
d+d=12
The numbers are 2,7,12
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