12. If cos (a + b) = 0 then sin (a-B) = ?
(a) sin a
(b) cos B
(c) sin 2a
(d) cos 2b
(URGENT FAST PLEASE)
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Answered by
1
Answer:
Step-by-step explanation:
Option B is correct.
Step-by-step explanation:
Given that cos(a+b)=0
then we have to find the reduced form of sin(a-b)
As, cos(a+b)=0
⇒ a+b=cos^{-1}(0)=90^{\circ}
⇒ a=(90-b)^{\circ}
sin(a-b)=sin(90-b-b)=sin(90-2b)=cos{2b}
Hence, sin(a-b)=cos{2b}
∴ option b) is correct.
Answered by
0
Answer:The given question is solved in the attachment
Step-by-step explanation:
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