12. In a class of 15 students, there are 5 girls. In how many
different ways can they be arranged in a row such that
no two of the five girls are consecutive?
Ans. Firstly if we fix the position of 10 boys then we get to know there are !10 possible ways to make them seated in a way that no two girls sit consequetive so for five girls eventually this creates 11 positions then 11p5 ways
that's why
!10×!11/(11-5)!= !10×!11/!5
Answers
Answer:
Given:
Given:Total number of students =10
Given:Total number of students =10There are 7 boys and 3 girls.
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row 7
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row 7 P
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row 7 P 7
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row 7 P 7
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row 7 P 7 =7!ways.
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row 7 P 7 =7!ways.So, 8 places in which we can arrange 3 girls are
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row 7 P 7 =7!ways.So, 8 places in which we can arrange 3 girls are 8
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row 7 P 7 =7!ways.So, 8 places in which we can arrange 3 girls are 8 P
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row 7 P 7 =7!ways.So, 8 places in which we can arrange 3 girls are 8 P 3
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row 7 P 7 =7!ways.So, 8 places in which we can arrange 3 girls are 8 P 3
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row 7 P 7 =7!ways.So, 8 places in which we can arrange 3 girls are 8 P 3 =
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row 7 P 7 =7!ways.So, 8 places in which we can arrange 3 girls are 8 P 3 = (8−3)!
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row 7 P 7 =7!ways.So, 8 places in which we can arrange 3 girls are 8 P 3 = (8−3)!8!
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row 7 P 7 =7!ways.So, 8 places in which we can arrange 3 girls are 8 P 3 = (8−3)!8!
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row 7 P 7 =7!ways.So, 8 places in which we can arrange 3 girls are 8 P 3 = (8−3)!8! =336ways
Given:Total number of students =10There are 7 boys and 3 girls.Seven boys can be arrange in a row 7 P 7 =7!ways.So, 8 places in which we can arrange 3 girls are 8 P 3 = (8−3)!8! =336waysThe number of arrangement is 7!×336ways.