Question

12. In AABC, ZB = 90° and D is the mid-point of
BC. Prove that ACP-AD2 + 3CD2 [2001]​

Answer 1

ummmmmm what ?

which class ?

Answer 2

Answer:

D is the midpoint of BC= AD = CD.

Angle B is a right angled triangle. ⇒ AC2 = AB^2 + (2BD)^2 (BC=BD+DC,BD=DC)

,So we can replace BC by 2BD