Math, asked by avantikasingh2002, 10 months ago

12.
In the circuit shown in figure, charge that passes through the battery
is 48 uС. Find the charge on capacitor C and the potential
difference across it.
3uF
6uF SUF
12
ht
o
2 F
4uF
12V​

Answers

Answered by Anithadevadiga
3

Answer:

I think question is wrong

Answered by vinod04jangid
0

Answer:

6V

Step-by-step explanation:

Given:- Charge passing through the battery = 48 uC.

To Find:- Charge on capacitor C and potential difference across C.

Formula Used:- Charge = Capacitance × Voltage.

                            Voltage = Charge / Capacitance, where we denote

                                                                                    voltage as V,

                                                                                   Capacitance as C and

                                                                                    Charge as Q.

                         Total capacitance when capacitors are in series i.e.

                                     \frac{1}{C_{eq} } = \frac{1}{C_{1} } + \frac{1}{C_{2} } + \frac{1}{C_{3} } + ......

                         Total capacitance when capacitors are in parallel i.e.

                                    C_{eq} = C_{1} + C_{2} + C_{3} + .......

Solution:-

#SPJ3

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