Question

12*root2/root3+root6

Answer 1

the answer is 10 √6......

Answer 2

Simplify:

Step-by-step explanation:

$\ Given \ value:\\\\\frac{12 \times \sqrt{2}}{ \sqrt{3} +\sqrt{6}}\\\\\ Solution:\\\\\frac{12 \times \sqrt{2}}{ \sqrt{3} +\sqrt{6}} \\\\\rightarrow \frac{2\sqrt{3}\times\sqrt{2}}{\sqrt{3} +\sqrt{6}}\\\\\rightarrow \frac{2\sqrt{6}}{\sqrt{3} +\sqrt{6}}\\\\\rightarrow \frac{2\sqrt{6}}{\sqrt{3} +\sqrt{6}} \times \frac{\sqrt{3}-\sqrt{6}}{\sqrt{3} -\sqrt{6}}\\\\\rightarrow \frac{2\sqrt{6}(\sqrt{3}-\sqrt{6})}{(\sqrt{3})^2- (\sqrt{6})^2}$

$\rightarrow \frac{2\sqrt{6}\sqrt{3}-2\sqrt{6}\sqrt{6})}{(\sqrt{3})^2- (\sqrt{6})^2} \\\\\rightarrow \frac{2\sqrt{6}\sqrt{3}-2\sqrt{6}\sqrt{6}}{3- 6} \\\\\rightarrow \frac{2\times 3\sqrt{2}-2\times 6}{(-3)} \\\\\rightarrow \frac{6\sqrt{2}-2\times 6}{(-3)} \\\\\rightarrow {-2(\sqrt{2}-2)} \\\\\rightarrow {(4-2\sqrt{2})}$

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