Question

12. Simplify 1 + (75)3 *
(1 Point)
O 135/132
0 29/25
O 133/125
O 16/33​

Answer 1

Answer:

(i) 135

Since, 5=20×51

⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.

So, the decimal form of 135 will be terminating type.

(ii) 211

Since, 11=20×50×111

⇒ The denominator is not in the form of 2m×5n, where m and n are non-negative integers.

So, the decimal form of 211 will be non-terminating recurring type.

(iii) 2916

Since, 16=24×50

⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.

So, the decimal form of 2916 will be terminating type.

(iv) 17125

Since, 125=20×53

⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.

So, the decimal form of 17125 will be terminating type.

(v) 116

Since, 6=21×50×31

⇒ The denominator is not in the form of 2m×5n, where m and n are non-negative integers.

So, the decimal form of 116 will be non-terminating recurring type.

Step-by-step explanation:

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