Question

12. The diagonal of a rectangle is thrice its
smaller side. Find the ratio of its sides.​

Answer 1

Answer:

$\sqrt{ { x}^{2} + {y}^{2} } = 3y \\ \\ sobs \\ {x }^{2} + {y}^{2} = 9 {y }^{2} \\ {x}^{2} = 8 {y}^{2} \\ x \div y = 2 \sqrt{2 } \\ therefore \: x \: \: is \: 2 \sqrt{2} \: of \: y$