12. What is the height of the tower if a freely falling body covers half of its
journey from the top of a tower in 0.5s.
(b) 2.45m
(a) 9m
(cy 4.9m
(d) 9.8m
Answers
Answered by
6
ANSWER :
Height of the tower is 2.45 m
EXPLANATION :
Let height of the tower be 2x
Distance covered is half the height
So distance covered is x
Since the body starts from rest, u=0m/s
t = 0.5 sec
a=g=9.8m/s²
s = ut + 1/2 at²
x = 0 + 0.5 × 9.8 × 0.5 × 0.5
x = 1.225
So it travelled 1.225 m in 0.5 sec
Height = 2x = 2× 1.225 = 2.45 m
So height of the tower is 2.45 m
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Answered by
1
the height of the tower is 2.45 meter
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