Question

120 = 2 power a × 3 power b ×5 power c then A+B+C =

Answer 1

Answer:

$120 = {2}^{3} \times 3 \times 5 \\ {2}^{a} \times {3}^{b} \times {5}^{c } = {2}^{3} \times 3 \times 5$

Therefore, A+B+C=5

Answer 2

Given:

120=2 power a×3 power b×5 power c

To find:

The value of A+B+C

Solution:

The value of A+B+C is 5.

We can find the value by following the steps given below-

We know that the sum of A, B, and C can be calculated by factorizing 120.

We will factorize 120 and express it as a product of its factors.

So, the factors of 120=3×5×8

The factors of 120=$2^{3}$×3×5

We are given that 120=$2^{a}$×$3^{b}$×$5^{c}$

On comparing the two equations, we get that

A=3, B=1, and C=1

Now, we will add these to get the required sum of A, B, and C.

A+B+C=3+1+1

A+B+C=5

Therefore, the value of A+B+C is 5.