Question

13. A particle is moving along straight line whose
velocity (v)-time (t) graph is shown. The distance
travelled by the particle is

(1) 1m
(2) 5 m
(3) 4 m
(4) 9 m​

Answer 1

Answer:

the correct answer is option b bcoz velocity is the ratio of distance and time so from the given figure let the time be 1 sec and velocity be 5 m/s so it gives the solution as 5m

Answer 2

We know that

X=vt OR AREA UNDER CURVE

Hence

from

first triangle

x=vt

X1=1/2Base ×Height

$x1 = \frac{1}{2} \times bh$

$x1 = \frac{1}{2} \times 5 \times 1 = 2.5m$

X2 area of rectangle = l×b=1×4=4m(since distance cannot be negative)

X3 are of second triangle=1/2b×h

$x3 = \frac{1}{2} \times 5 \times 1 = \frac{1}{2} \times 5 = 2.5$

total distance=9m