Math, asked by veer378, 1 year ago

13) A Rectangle park is 32 m long and 15 m wide find its
perimeter and area​

Answers

Answered by niral
2

Answer:

Step-by-step explanation:

→ length of rectangle=32 m

→ breadth of rectangle= 15m

→ perimeter of rectangle= 2(l+b)

                                        =2(32+15) = 2(47) = 94 m

→ area of rectangle= l×b

                                = 32×15

                                  =480m²


niral: mark me as brainliest answer.
Answered by Pricilla
5

SOLUTION :-

\underline{\bf{\sf{\huge{Given \: }}}}\to

 \rm{Lenth \:  \: of \:  \: the \:  \: rectangular \: \: park \:  = 32 \:  \: m } \\  \\  \rm{Width \:  \: of \:  \: the \:  \: rectangular \:  \:park \:  = 15 \:  \: m}

 \underline{ \bf{\sf{\huge{ \:  We \:  \:  \: know \:  \: that \:  \: }}}}

 \boxed{\boxed{\rm{Perimeter \:  \:  \: of \:  \:  \: a \:  \:  \: rectangle \:  = 2(length  + width)}}}

 \rm{ \therefore \:  \:  \: Perimeter \:  \: of \: \: the \:  \: rectangular \:  \: park } \\  \\  \rm{ = 2(32 + 15) \:  \: m} \\  \\  \rm{ = (2 \times \: 47) \:  \: m} \\  \\  \rm{ =  \underline{94 \:  \: m}}

\bf{\sf{\huge{ \: Again \:}}}

 \underline{ \bf{\sf{\huge{ \:  we \:  \:  \: know \:  \: that \:  \: }}}}

 \boxed{ \boxed{ \rm{Area \:  \:  \: of \:  \:  \:a  \:  \: rectangle \:  = length \times width}}}

 \rm{ \therefore \:  \:  \: Area \:  \:  \: of \:  \:  \: the \:  \:  \: rectangular \:  \:  \: park} \\  \\  \rm{ = (32 \times 15) \:  \: m {}^{2} } \\  \\  \rm{ = \underline{ 480 \:  \: m {}^{2} }}

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