Question

13. Calculate the difference between the
compound interest and the simple interest
on 8,000 in three years at 10% per
annum.
Please find it ​

Answer 1

$\sf\large\underline{Given:}$

$\tt{\implies Principal=8000}$

$\tt{\implies Rate=10\%}$

$\tt{\implies Time=3\: year}$

$\sf\large\underline{To\: Find:}$

$\tt{\implies Difference\:_{(CI-SI)}=?}$

$\sf\large\underline{Solution:}$

• At first calculate the both CI and SI separately than subtracting eachother]

$\sf\small\underline{Calculation\:for\:CI:}$

$\tt{\implies CI=P\bigg(1+\dfrac{r}{100}\bigg)^n-P}$

$\tt{\implies CI=8000\bigg(1+\dfrac{10}{100}\bigg)^3-8000}$

$\tt{\implies CI=8000\bigg(\dfrac{100+10}{100}\bigg)^3-8000}$

$\tt{\implies CI=8000\bigg(\dfrac{110}{100}\bigg)^3-8000}$

$\tt{\implies CI=8000\bigg(\dfrac{11}{10}\bigg)^3-8000}$

$\tt{\implies CI=8000\times\dfrac{11}{10}\times\dfrac{11}{10}\times\dfrac{11}{10}-8000}$

$\tt{\implies CI=8\times1331-8000}$

$\tt{\implies CI=10648-8000}$

$\tt{\implies CI=2648}$

$\sf\small\underline{Calculation\:for\:SI:}$

$\tt{\implies SI=\dfrac{P\times\:T\times\:R}{100}}$

$\tt{\implies SI=\dfrac{8000\times\:3\times\:10}{100}}$

$\tt{\implies SI=80\times\:3\times\:10}$

$\tt{\implies SI=2400}$

$\bf\large{Hence,}$

$\tt{\implies Difference\:_{(CI-SI)}=2648-2400}$

$\tt{\implies Difference\:_{(CI-SI)}=248}$

Answer 2

Answer:

compound interest

P=Rs.8000

R=10%

T=3year

Amount =9448

CI =A-P 9448-8000=1448

Simple interest

P=8000

R=10%

T=3year

SI=8000x10x3/100=2400

difference between

2400-1448=952