Question

13. The debroglie wavelength of an electron is 1.226angstrom. What is thevalue of accelerating potential?50 voltsO100 voltsO 150 voltsO 200 volts​

Answer 1

Answer:

Using energy conservation, KE=PE or

2m

p

2

=eV or p=

2meV

where p= momentum of electron, m= mass of electron, e= charge of electron and V= potential difference.

Now, de-Broglie wavelength λ=

p

h

=

2meV

h

=

2(9.1×10

−31

)(1.6×10

−19

)(100)

6.6×10

−34

=1.22×10

−10

Explanation:

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