Question

(13) The perimeter of rhombus is 100 cm and
one of its diagonals measures 48 cm.
Then, the length of the other diagonal
is



step by step explanation is needed ​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

4a=100

a=25a=25

The measure of each side is 25.

4a^2=d_1^2+d_2^24a

2

=d

1

2

+d

2

2

Where, a is side length and d₁ and d₂ are diagonals.

4(25)^2=(48)^2+d_2^24(25)

2

=(48)

2

+d

2

2

2500=2304+d_2^22500=2304+d

2

2

d_2=\sqrt{2500-2304}d

2

=

2500−2304

d_2=14d

2

=14

The area of rhombus is

A=\frac{1}{2}(d_1d_2)A=

2

1

(d

1

d

2

)

A=\frac{1}{2}\times 48\times 14A=

2

1

×48×14

A=336A=336