Question

13 yrs back my fathers age was thrice my age and 2 yrs back he was twice of age. find the present age of father

Answer 1

Lets represent the age of the father as x and the age of the son as y.

13 years ago x was thrice y's age, or

(x - 13) = 3(y - 13); or

x - 3y = -26

2 years ago, x was twice y's age, or

(x - 2) = 2 (y - 2); or

x - 2y = -2

Subtracting equation 1 from 2:

x - 2y - (x - 3y) = -2 - (-26)

or

y = 24

Then x = -2 + 2y = 46

Thus age of the Father is 46 and age of the son is 24