Question

139.a constant force of 12N acts 1 point
on a body for 4s.the change in
the linear momentum of
the,body is *
O 48kgms-
0.48kgms-
O 4.8kgms-
O 480kgms-​

Answer 1

Answer:

48 kgm/s option 1 is correct

Explanation:

$f = \frac{dp}{dt}$

$12 = \frac{dp}{4 - 0}$

$dp = 12 \times 4 = 48kgm {s}^{ - 1}$

Plz mark brainliest

Answer 2

Answer:

48 kgm/s option 1 is correct

Explanation:

F=dp/4-0

dp=12×4 = 48 kgms-1

I Hope answer is hopefully

Pleases make me brainliest