Question

13cos=5 find tna^2-sec^2​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Cos= 5/13

P=√h^2-b^2

√13^2-5^2

√144

12

Tan^2 =p/b

( 12/5)^2

144/25

Sec^2= h/b

(13/5)^2

169/25

Tan^2-sec^2

144/25-169/25

-25/25

-1