13sinA=5 , 5sinA-2cosA÷tanA=?
Answers
Answered by
1
Answer:
12/65
Step-by-step explanation:
sinA=5/13 , cosA = 12/13
5sinA-2cosA÷tanA=? = N
N = 5sinA-2cosA÷tanA = 5x5/13-2x12/13÷5/12 = 1/13x12/5 = 12/65
Answered by
1
Answer:sinA=5/13
By PGT
The value of sin=p/h
So, h^2=p^2+b^2
13×13= 5×5+b^2
169=25+ b^2
By transposing
169-25 =b^2
144=b^2
Remove square
UnderRoot144=base
Base =12
5×5/13- 2× 12/13/ 5/13
25/13-24/13 /5/13
1/13/5/13
Ans=1/5
Thank you
It will help you
Step-by-step explanation:
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