14. In the given figure, AP = BQ, PR =BQ, PR = QS.
Show that AAPS = ABQR
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In △APB and △AQB
AP=AQ (Given)
BP=BQ (Given)
AB=AB (Common Side)
∴△APB≅△AQB(S.S.S. congruency)
⇒∠PAB=∠QAB(C.P.C.T.C.)
⇒∠PBA=∠QBA(C.P.C.T.C.)
Thus, AB is bisector of ∠PAQ and ∠PBQ
Step-by-step explanation:
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