Question

14. Which of the following compound could be prepared by reacting Bromoethane with Potassiun
cyanide and then reducing the product?

A) CH3CH3

B)CH3CH2NH2

C)CH3CH2CH2NH2

D)CH3CH2CH3


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Answer 1

Answer:

(c)

CH3CH2Br +KCN = CH3CH2CN and its reduction will produce CH3CH2CH2NH2

Answer 2

Answer: (C) CH3CH2CH2NH2

Explanation:

CH3CH2Br + KCN  ⇒ CH2CH2CN  (on reduction it will produce) ⇒CH3CH2CH2NH2