Question

14(z+3)=14z+21
how many solutions does this equation have?

Answer 1

Hey mate,...

=>Step 1 :

Equation at the end of step 1 :

14 • (z + 3) - (14z + 21) = 0

=>Step 2 :

Equation at the end of step 2 :

21 = 0

=>Step 3 :

Equations which are never true :

3.1 Solve : 21 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Hope it will help you.

✨Sai.

Answer 2

Answer:

No solution .

Step-by-step explanation:

14 ( z + 3 ) = 14 z + 21

Multiply and open the bracket in L.H.S

⇒ 14 z + 42 = 14 z + 21

Transpose the numeric value to the R.H.S

⇒ 14 z = 14 z + 21 - 42

Transpose the unknown value to the L.H.S

⇒ 14 z - 14 z = - 21

Now we assume that z is a solution to the equation .

Then we will have 0 = -21 which is impossible .

For any value of z , the solution will never be satisfied .

Hence there are no solutions to the equation .