Question

14g of CO at 27c is mixed with 16g of O2 at 47c. the temperature of the mixture is

Answer 1

no. of moles of co = mass/molar mass

                              =14/28

                               =0.5mole

no. of moles of o2=16/32

                              =0.5 mole

since both have the same no. of moles the resulting temperature will be the average of both their temperatures.

∴ the temperature of the mixture is = (27 + 47)/2

                                                             =37 c

Answer 2

Answer:

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Explanation:

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