Question

15, 20, 25, 30 and 35 respectively.
15. Find the least number of five digits which on dividing by 10, 12, 16, 20, 25 and
30 leaves remainder 8 in each case.
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Answer 1

Answer:

1208

Step-by-step explanation:

LCM of 10 , 12 , 16 , 25 and 30 = 1200

so the required no is 1200 + 8 = 1208

Answer 2

Answer:

6308

Step-by-step explanation:

LCM OF 15,20,25,30,35= 6300

SINCE, IT LEAVES A REMAINDER 8 IN EACH CASE

THE LEAST NO. OF THE 5 DIGITS=

=6300+8

=6308

hope it will help you